For loop inside structure

I have a structure called (level3) and inside it some fields (e.g x0, vx). each field is an array with some values as shown in the screenshot.
I would like to go through these fields values and multply them as follows:
x(1,1)*vx(1,1)
x(2,1)*vx(2,1)
x(3,1)*vx(3,1)
.... and so on.
so I got at the end 10 arrays of results of x
I tried to do it like this but I just got one array with the last value.
fields = fieldnames(level3);
for k=1:10
x = [x0. * vx];
end
Thanks in advance

 Risposta accettata

Mohammed Hammad
Mohammed Hammad il 25 Gen 2019
Modificato: Mohammed Hammad il 26 Gen 2019

0 voti

I got the answer after many tries as follows:
for n = 1:10
x{n} = level3(n).x0. * (level3(n).vx)
end

2 Commenti

Stephen23
Stephen23 il 26 Gen 2019
Modificato: Stephen23 il 26 Gen 2019
Those square brackets are superfluous. Get rid of them.
Note that your inner loop serves no purpose, because you do not use its loop index anywhere and none of its iterations depend on previous iterations, so the results of every of its iteration will get discarded except for the last one.
Thank you for your notes. yeah I removed the inner loop and I got the desired results.

Accedi per commentare.

Più risposte (1)

Bob Thompson
Bob Thompson il 24 Gen 2019

1 voto

fields = fieldnames(level3);
for k=1:10
x = [x0. * vx];
end
If I understand this correctly you're trying to capture the array of multiplications (x0 .* vx) for all of the different elements of the structure. I believe that all you're missing then is either an index on x, or to concatonate the results of x with the previous values.
fields = fieldnames(level3)
x = [];
for k = 1:10
x = [x;[x0.*vx]];
end

1 Commento

It works , thank you. but the answer is Double(50*1) and I want it 10 arrays, each array has different number of values. the length must be the same as x0 and vx arrays length

Accedi per commentare.

Categorie

Scopri di più su Loops and Conditional Statements in Centro assistenza e File Exchange

Prodotti

Release

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by