Azzera filtri
Azzera filtri

Info

Questa domanda è chiusa. Riaprila per modificarla o per rispondere.

Need help with a while loop to take numbers off.

1 visualizzazione (ultimi 30 giorni)
Nicolo Zaza
Nicolo Zaza il 21 Lug 2012
Chiuso: MATLAB Answer Bot il 20 Ago 2021
Alright so I have counting algorithm but i need it to extract elements from an original source and after extracting them and storing I need matlab to discard them so they dont get count again. How do i do this? My code: if true
DATA = [ 60 0 40 -20 40 -40 50 -30 30 -60 0 -30 40 -30 60];
L = length(DATA);
E = [1:L];
N = 1;
while N < L
N = N + 1;
if N < 3
continue
end
X(N) = [abs(DATA(N)-DATA(N-1))];
Y(N) = [abs(DATA(N-1)-DATA(N-2))];
if X < Y
continue
else
RANGE(N) = Y(N);
XMEAN(N) = [.5*(DATA(N-1)+DATA(N-2))]
DATA (N -2) = []
DATA (N-1) = []
N = N - 2
end
for I = N:L
L = L - 2
E(I) = E(I+1);
end
end
end
  1 Commento
Nicolo Zaza
Nicolo Zaza il 21 Lug 2012
Sorry to not finish expressing my question. So what I'm using right now is if true
DATA(N-2) = []
&
DATA(N-1) = []
end
to delete the values used to calculate RANGE because once range is calculated I dont need to calculate it again for those same points. Is there a better matlab function/code to accomplish this need?

Risposte (1)

Image Analyst
Image Analyst il 21 Lug 2012
Modificato: Image Analyst il 21 Lug 2012
Yes, that will delete elements but you're indexing elements and that will change, not to mention the length of your DATA array keeps getting shorter as you delete elements to eventually as N approaches L you'll get an index out of range error.
What are you really trying to do? Can't you just extract arrays and subtract them, and use diff? Or use hist if you want to count values?
data_n = DATA(3:end)
data_nm1 = DATA(2:end-1)
data_nm2 = DATA(1:end-2)
X = abs(data_n - data_nm1)
Y = abs(data_n - data_nm2)
RANGE = y
xMean = 0.5 * (data_nm1 - data_nm2)
% I have no idea what E is supposed to represent.
  3 Commenti
Nicolo Zaza
Nicolo Zaza il 21 Lug 2012
Yes I've seen it but is written in C and is hard to manipulate for me. I dont have much programming knowledge. Besides the program I need is pretty simple compared to that

Questa domanda è chiusa.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by