How to return answer in 8 columns of 2D matrices through division

I need to create 8 columns of matrices based on division of 2 separate sets of matrices. My code below:
PhysicalThickness=[0,5,10,15,20,25,30,35];
for i=1:length(PhysicalThickness)
h=num2str(i-1);
fileextension='.dcm';
filenameEN=strcat(XIOM0,h,fileextension);
filenameEX=strcat(XIO,h,fileextension);
[OPEN]=dicomread(filenameEN);
[data]=dicomread(filenameEX);
rTPS=data./OPEN;
end
%______________________________________________________________________%
PhysicalThickness=[0,5,10,15,20,25,30,35];
for j=1:length(PhysicalThickness)
h=num2str(j-1);
fileextension='.dcm';
EPIDfilenameEN=strcat(EPIDM0,h,fileextension);
EPIDfilenameEX=strcat(EPID,h,fileextension);
[OPEN]=dicomread(EPIDfilenameEN);
[data]=dicomread(EPIDfilenameEX);
rEPID=data./OPEN;
end
%____________________________________________________________________%
ratio=rTPS./rEPID;
rTPS and rEPID, both returned answer in 8 columns of PhysicalThickness (which is what I want). However, when I divide the product of the two (rTPS./rEPID), I get only 1 answer (belonging to the last PhysicalThickness).
How do I get the answer for all i/j (PhysicalThickness) in 8 columns instead of just one?

 Risposta accettata

Jan
Jan il 23 Lug 2012
Modificato: Jan il 23 Lug 2012
The problem appears, because you overwrite rTPS and rEPID in each iteration. The solution is to read both input and calculate the results inside the loop:
PhysicalThickness=[0,5,10,15,20,25,30,35];
ratio = cell(1, length(PhysicalThickness));
for i=1:length(PhysicalThickness)
h=num2str(i-1);
fileextension='.dcm';
filenameEN=strcat(XIOM0,h,fileextension);
filenameEX=strcat(XIO,h,fileextension);
OPEN=dicomread(filenameEN);
data=dicomread(filenameEX);
rTPS=data./OPEN;
%
EPIDfilenameEN=strcat(EPIDM0,h,fileextension);
EPIDfilenameEX=strcat(EPID,h,fileextension);
OPEN=dicomread(EPIDfilenameEN);
data=dicomread(EPIDfilenameEX);
rEPID=data./OPEN;
%
ratio{i} = rTPS./rEPID;
end
Or if you want to store the results as [m x n x r] array add this after the loop:
ratio = cat(3, ratio{:});

Categorie

Scopri di più su Loops and Conditional Statements in Centro assistenza e File Exchange

Tag

Richiesto:

il 23 Lug 2012

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by