'Value' must be a double scalar error?

In my GUI I am trying to display some numerical values related to projectile motion. However, I keep getting the message, 'Value' must be a double scalar, when I try to display values for the range and the horizontal position at max height. Values for max height and flight time output just fine, and I cannot tell the difference between the type of values used in the equations. Furthermore, I have tried using the double command and the str2double command in attempts to change the value type, but neither are enabling me to display range or horizontal position values. What am I misunderstanding here?

Below is the relevant code:

gE  = 9.81;
vix = v0*cosd(angle);
viy = v0*sind(angle);
hangtime1 = 2*viy/gE;
t1 =        0:hangtime1/50:hangtime1;
x1 =        x0+vix.*t1;
maxheight1= y0 + (viy)^2./(2*gE);
xheight1  = x0 + vix.*(t1./2);
range1    = vix*t1;
r1        = double(range1);

% values I want to display; also want to include horizontal position, which is the variable xheight1
app.Hangtime.Value=hangtime1 
app.MaxHeight.Value=maxheight1
app.Range.Value=r1

Thanks for your help out there!

Answer 1

[Guillaume]

Trying things at random (such as str2ouble) is not a good way to solve problems. The error message is clear, Value must be a scalar double, so clearly whatever you're passing is not a double or is not scalar. You are using double (and there's no need of the double(...) conversion which doesn't do anything), so the problem must be that the numbers are not scalar. Sure enough:

t1 =        0:hangtime1/50:hangtime1;
%...
range1    = vix*t1;          %since t1 is an array, so is range1
r1        = double(range1);   %doesn't do anything range1 is alreay double
%...
app.Range.Value=r1

You need to decide which value of range1 you want to pass to your control, or make sure range1 is scalar.

[Ryan Schofield]

Thank you, Guillame! I had overlooked the fact that variable t1 was an array.

[Eduar Yesid]

por lo que se puede observar el error se da porque el valor de la variable T1 es un error, es decir es como si estubieras dividiendo 1/0. Para solucionar el error debes asegurarte que el valor de T1 es un numero valido