Azzera filtri
Azzera filtri

vpasolve in for loop

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maedeh Gh
maedeh Gh il 19 Feb 2019
Commentato: Etsuo Maeda il 5 Mar 2019
I Run this code and it works correctly, but I wanna stop the for loop when it gets Empty sym: 0-by-1
for p=0:10
ub= vpasolve(function==0,x,[1000*p,1000*(p+1)])
end

Risposte (1)

Etsuo Maeda
Etsuo Maeda il 5 Mar 2019
"vpasolve" returns numerical values. Its output "ub" cannot be a sym variable. If you use "solve", you can use "isempty" and "break" for your pourpose.
syms x
for k = 1:2
out = solve(x^k + 1 == 0, x)
if isempty(out) == 1
disp('break')
break;
end
disp('in loop')
end
HTH
  2 Commenti
Walter Roberson
Walter Roberson il 5 Mar 2019
This is not quite correct. vpasolve() returns symbolic values that represent numeric values. They are sym, and when no solution is found then the empty sym can be returned.
Also there is no need to compare isempty() to 1: you can just test if isempty(out)
Etsuo Maeda
Etsuo Maeda il 5 Mar 2019
UUUps, thank you very much for your kind correction :-)

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