How to replace variable name in function handle?

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I have a function handle as given below
f = @(x1,x2) x1*x2
and I want to change variable name to
f = @(x) x(1)*x(2)
Please help me
Thanks
PS: The function is just for illustration purpose
  1 Commento
Marco Aurélio
Marco Aurélio il 9 Lug 2024
Hello Matlab mate.
I think you must redefine de function handle just rewriting like this:
f=@(x) prod(x);

Accedi per commentare.

Risposta accettata

Stephan
Stephan il 25 Feb 2019
Modificato: Stephan il 25 Feb 2019
Hi,
for me this worked:
f = @(x1,x2) x1*x2
f = string(char(f));
f = replace(f,"@(x1,x2)","@(x)");
f = replace(f,["x1","x2"],["x(1)","x(2)"]);
f = str2func(f)
result is:
f =
function_handle with value:
@(x1,x2)x1*x2
f =
function_handle with value:
@(x)x(1)*x(2)
Best regards
Stephan
  2 Commenti
madhan ravi
madhan ravi il 25 Feb 2019
Modificato: madhan ravi il 25 Feb 2019
stephen what if there are 100 inputs to the function handle? it would be not a good idea
Stephan
Stephan il 25 Feb 2019
Modificato: Stephan il 25 Feb 2019
You are right. But i think this function is worth to be shown here as an alternative for small examples. Maybe it is not the best / most efficient solution here. Yours is pretty nice - but the OP asked for how to replace variable names in a function handle - this is what i was answering to.

Accedi per commentare.

Più risposte (1)

madhan ravi
madhan ravi il 25 Feb 2019
Instead of converting it to your later need convert the vector as comma separated list using num2cell():
x=rand(1,2); % example vector
X=num2cell(x);
f(X{:}) % pass the vector all at once

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