eliminate indices that are empty

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Suppose I have a vector of eliments including empty spaces in random places. How can I get the average of values that are available.
Example is as follows. Note that there is no value after 1 and 8. So I want to avoid those and get the average of the rest. Here I cannot just use the 'mean(x,1)' because empty indexes. Assume that I am considering a large vector and i cannot find the indices where there are no values, but just empty spaces.
X=[ 2 4 1 5 2 2 7 8 1 3]

Answers (1)

madhan ravi
madhan ravi on 30 Apr 2019
Edited: madhan ravi on 30 Apr 2019
X={ 2 4 1 [] 5 2 2 7 8 [] 1 3};
idx=cellfun('isempty',X);
X(idx)={NaN};
Wanted=mean([X{:}],'omitnan')
%or
Wanted=mean([X{~idx}])
  3 Comments
madhan ravi
madhan ravi on 30 Apr 2019
That's exactly what was posted.

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