How can I load .psv file to MATLAB?
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I have downlaoded datase from PhysioNet/Computing in Cardiology Challenge 2019. Here all the data are in .psv format. Can anyone help me showing the way of loading this format data.
5 Commenti
Diana Simona
il 11 Ott 2019
Modificato: Diana Simona
il 11 Ott 2019
Hey,
Have you figured it out how to do this?
Because i have encountered the same problem, i can't see and extract the values.
I can open the file and see the headers (HR|O2Sat|Temp|SBP|MAP|DBP|Resp etc). I can also see some values here and there, but i get a lot of NaN values.
ps: i dont have a lot of Matlab experience
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/242197/image.png)
Risposta accettata
Jan
il 9 Mag 2019
Modificato: Jan
il 13 Mag 2019
A small example would reveal, if this guess is correct: It is a pipe-separated text file. Then:
readmatrix(filename, 'Delimiter', '|', 'FileType', 'text')
[EDITED] And a dull manual method:
function [Data, Header] = ReadPSV(File)
% [Data, Header] = ReadPSV(File)
% INPUT:
% File: Char vector or string: Name of the file
% OUTPUT:
% Data: Double matrix, [nVariables x nFrames]
% Header: {nVariables x 1} cell string
%
% License: CC BY-SA 3.0
[fid, msg] = fopen(File, 'rt');
assert(fid ~= -1, 'Tools:ReadPSV:MissFile', ...
'Cannot open file:%s\n%s', File, msg);
Line1 = fgetl(fid); % Import 1st line
Header = strsplit(Line1, '|'); % Reply variables as cell string
n = numel(Header); % Number of variables
% [EDITED] start
str = fread(fid, [1, inf], '*char'); % Import data as string
str(str == char(10)) = '|'; % Replace line break by |
% [EDITED] end
Data = sscanf(str, '%f|', [n, inf]); % Extract numbers
fclose(fid);
end
3 Commenti
Jan
il 13 Mag 2019
@Walter: Thank you. Fixed. And the next bug was:
str(str = char(10)) = '|';
% ^ Of course: ==
Più risposte (1)
Ricardo Salinas Martinez
il 28 Mag 2019
Hello!
Jan's answer works preaty well, but if you read the codes provided by the challenge you will see how they read the files and there is no need for you to read them differently.
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