How do filter function work?

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Treant
Treant il 26 Ago 2012
Modificato: Sergio Cuadros il 18 Giu 2020
I understand how the filter(b,a,X) works. What confuses me is the function with the initial conditions. The function filter(b,a,X,zi).
for example: y(n)=-0.5y(n-1)+x(n) x(n)=u(n) y(-1)=1
how will the filter function solve this? i tried to do it manually, but i get different output.

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Honglei Chen
Honglei Chen il 26 Ago 2012
Modificato: Honglei Chen il 26 Ago 2012
MATLAB's filter() function an implementation of direction form II, the detailed algorithm can be found at
For your case, you need to first figure out what the initial condition is. You can use filtic function.
e.g.,
b = 1;
a = [1 0.5];
y = filter(b,a,ones(10,1),filtic(b,a,1));
  3 Commenti
Honglei Chen
Honglei Chen il 27 Ago 2012
It basically perform a reverse filtering operation. If you want the details, you can look at filtic code.
Sergio Cuadros
Sergio Cuadros il 18 Giu 2020
Modificato: Sergio Cuadros il 18 Giu 2020

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Jan
Jan il 27 Ago 2012
Modificato: Jan il 27 Ago 2012
You find a Matlab implementation of the FILTER command at Answers: hard-code-filter. This should reveal the meaning of the initial and final conditions.
Splitting a signal into parts might be helpful also:
signal = rand(1,1000);
[b,a] = butter(3, 0.5); % Arbitrary filter parameters
inital_cond1 = zeros(1, length(a) - 1);
[filtered1, final_cond1] = filter(b, a, signal(1:500), initial_cond1);
[filtered2, final_cond2] = filter(b, a, signal(501:1000), final_cond1);
Joined = [filtered1, filtered2];
% Now filter in one step:
OnePiece = filter(b, a, signal, initial_cond1);
% Compare the results - should be tiny:
disp(mean(abs(Joined - OnePiece)));
This shows, that the inital conditions are the values of the internal status of the filter. When the signal is split into pieces, the final conditions of the former part are the inital conditions of the current part.

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