How can I solve a nonlinear model using Newton Raphson ?

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Hi
How can I solve this nonlinear model using Newton Raphson ?
x1 +x2^2 +cos (x3) = 2
x1 +sin (x2) + x3^3 = 1
x3 +x2^3+x3^3 = 4

Risposta accettata

Stephan
Stephan il 25 Gen 2020
One way:
result = fsolve(@fun,[1 1 1])
function F = fun(x)
F(1) = x(1) + x(2).^2 + cos(x(3)) - 2;
F(2) = x(1) + sin(x(2)) + x(3).^3 - 1;
F(3) = x(3) +x(2).^3 + x(3).^3 - 4;
end
gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
result =
-0.5583 1.3732 0.8329
  2 Commenti
John D'Errico
John D'Errico il 25 Gen 2020
The best way to solve it. Don't use Newton-Raphson at all. :)
Mallouli Marwa
Mallouli Marwa il 25 Gen 2020
If I want to use Newton Raphson.
How can we change it ?

Accedi per commentare.

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