acces data in struct
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Rica
il 19 Lug 2019
Commentato: Mario Chiappelli
il 19 Lug 2019
Hi!
I have a struct Str. the element of the structure arle A, B, C,.... all of the are arrays with length 2000. I want to have onle the element from 500:1500 without writing
Str.A1=Str.A(500:1500) for every struct element.
is there an easy way to achieve this goal?
thank you!
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Risposta accettata
Peter Jarosi
il 19 Lug 2019
Modificato: Peter Jarosi
il 19 Lug 2019
You can use for loop indexing elements of your structure:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
e2 = strcat(e1, '1');
Str.(e1)=Str.(e2)(500:1500);
end
Please, let me know if it works for you
2 Commenti
Peter Jarosi
il 19 Lug 2019
Modificato: Peter Jarosi
il 19 Lug 2019
You're very welcome!
You are right, if you want to overwrite your existing instances. In this case strcat() is even unnecessary:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
Str.(e1)=Str.(e1)(500:1500);
end
but in your question you wrote:
Str.A1=Str.A(500:1500);
that's why I thought that you want to create new elements of your structure in order to save old ones.
Più risposte (2)
Mario Chiappelli
il 19 Lug 2019
Modificato: Mario Chiappelli
il 19 Lug 2019
I would loop through each A,B,C... Other languages call this a for each loop.
for str = {'A','B','C'}
variableName = strcat(str{1},'1');
Str.(variableName) = Str.(str{1})(500:1500);
end
Note: Instead of looping through numbers where each iteration is stored in the for statement variable "i" (or whatever you decide to call it), you are looping through each letter and the for statement variable in this case is "str".
6 Commenti
Peter Jarosi
il 19 Lug 2019
Good job! I've given you a vote for it.
One little thing is left. Change "1" to '1'
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