Does blockproc() divide the image into overlapping or non-overlapping blocks?
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So I'm exploring ways to split an image into blocks and applying DCT on each blocks of the image and i came across this example https://www.mathworks.com/help/images/discrete-cosine-transform.html
It uses the blockproc() function to first split the image into 8x8 blocks and apply DCT after. Is the blockproc() function dividing the image into overlapping or non-overlapping blocks since I'm working on copy move forgery detection?
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  Walter Roberson
      
      
 il 8 Ago 2019
        In the form used in that example, blockproc() is using non-overlapping blocks.
The blockproc option 'BorderSize' permits you to define overlapping, if you want overlapping.
    'BorderSize'        A 2-element vector, [V H], specifying the amount of
                        border pixels to add to each block.  V rows are
                        added above and below each block, H columns are
                        added left and right of each block.  The size of
                        each resulting block will be:
                            [M + 2*V, N + 2*H]
                        The default is [0 0], meaning no border.
                        By default, the border is automatically removed
                        from the result of FUN.  See the 'TrimBorder'
                        parameter for more information.
                        Blocks with borders that extend beyond the edges of
                        the image are padded with zeros.
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  Guillaume
      
      
 il 10 Ago 2019
				Note that not all combinations of window size and sliding step can be achieved this way. The window size minus the sliding step must be a multiple of 2.
Also note, that this means that the image will be automatically padded on all sides with 0s.
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