How to convert RGB to CIE Lab color space?

 Risposta accettata

Convert the image to L*a*b* color space using makecform and applycform.
colorTransform = makecform('srgb2lab');
lab = applycform(rgbImage, colorTransform);

7 Commenti

How to seperate L, a and b?
L_Image = lab(:, :, 1); % Extract the L image.
A_Image = lab(:, :, 2); % Extract the A image.
B_Image = lab(:, :, 3); % Extract the B image.
I want to first quantize the RGB color space to 16 levels then I want to convert it to Lab color space. How can this be done.
This works well when, RGB color space have values between [0-255]
colorTransform = makecform('srgb2lab');
lab = applycform(rgbImage, colorTransform);
Divide by 16, then make sure it's an integer (uint8). Then convert to lab. Or multiply by 16 and convert to lab, depending on what you want to do.
I want to convert rgb images to lab. But above code is not working.It not shows any output after the conversion.Help me out
Adam
Adam il 4 Gen 2017
Modificato: Adam il 4 Gen 2017
doc rgb2lab
if you have >= R2014b and Image Processing Toolbox which you need for the above anyway (the toolbox)
zee, you can also use rgb2lab(). But, what output are you expecting? You get an image. And to see that image you can use imshow(), or you can just look at its values in the variable editor in the workspace. But no output will get "shown" unless you do one of those two things. Otherwise all you get is a new variable.
If you want to see the 3-D color gamut, you can use colorcloud() (R2016b and later).

Accedi per commentare.

Più risposte (3)

Deepak Panda
Deepak Panda il 13 Ott 2015
How can I transfer rgb to Lab color space with luminance [0 100], a [-86.18 98.23] and b [-107.86 94.47]

5 Commenti

Try this:
rgb2lab([1 1 1])
rgb2lab(uint8([255, 255, 255]))
rgb2lab(uint8([255, 0, 0]))
rgb2lab(uint8([0, 255, 0]))
rgb2lab(uint8([0, 0, 255]))
ans = 100 0.017536 -0.0061222
ans = 100 0.017536 -0.0061222
ans = 53.233 80.119 67.221
ans = 87.737 -86.176 83.183
ans = 32.303 79.204 -107.86
So a seems to go from about -86 to +80 and b seems to go from about -107 to +83. Why do you want something different? How will it help you?
I am following this paper.
Onur Kucuktunc, Ugur Gudukbay, and Ozgur Ulusoy. Fuzzy Color Histogram-based Video Segmentation. Computer Vision and Image Understanding, 114(1):125–134, 2010.
The authors have used L [0 100], a [-86.18 98.23] and b [-107.86 94.47].
Deepak Panda
Deepak Panda il 14 Ott 2015
Modificato: Walter Roberson il 14 Ott 2015
Is there any difference between these two procedures of rgb to lab conversion
1. colorTransform = makecform('srgb2lab');
lab = applycform(rgbImage, colorTransform);
2. rgb2lab
I wouldn't think so. Try it and see.
If you have higher version than 2014....just rgb2lab is sufficient to convert the image to lab color space

Accedi per commentare.

Yoon ThiriZaw
Yoon ThiriZaw il 14 Giu 2019
Can we calculate rgb to lab without matlab code using hand calculation?

3 Commenti

Of course. There are formulae. I don't know where, offhand, but it's just maths and I'm sure you are as able as me at doing an internet search to find it.
Try here: easyrgb.com
0001 Screenshot.png
First go from RGB to XYZ, then XYZ to LAB.
Or you could try Bruce Lindbloom's site
0000 Screenshot.png
The above are just images so you can't click on them. But click on the link and go to the site and click on the formula you want and it will be there.
Just be aware that your LAB values will NOT be the same as what you get from a spectrophotometer, unless you do a calibration.
Thanks all!!!

Accedi per commentare.

kasthuri c
kasthuri c il 10 Lug 2019
how to find the values of L paramete a parameter b parameter in Lab conversion method.

1 Commento

labImage = rgb2lab(rgbImage);
LImage = labImage(:, :, 1);
aImage = labImage(:, :, 2);
bImage = labImage(:, :, 3);

Accedi per commentare.

Categorie

Scopri di più su Convert Image Type in Centro assistenza e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by