List(Vecor) Generation

Can I generate list [1 2 3 2 3 4 3 4 5 4 5 6 ....] without for loop?

Thanks!

Answer 1

[madhan ravi]

m=3; % pairs 
n=4; % n combinations
reshape((0:n-1)+(1:m)',1,[])

[madhan ravi]

If you're using version prior to 2016b:

% last line would be
reshape(bsxfun(@plus,(0:n-1),(1:m)'),1,[])

Answer 2

[Walter Roberson]

T=1:3*n;
Vec = floor(T/3) + mod(T-1,3) + 1;

[Junjie Liao]

The output is 1 2 4 2 3 5 3 4 6 :(

[Junjie Liao]

Correct answer should be Vec = floor(T/4) + mod(T-1,3) + 1.

Thanks!

Answer 3

[Andrei Bobrov]

m=3;
n=4;
T = 1:m*n;

out = ceil(T/m) + mod(T-1,m);

or

out = floor(T/n) + mod(T-1,m) + 1;

or

out = repmat(1:m,1,n) + repelem(0:n-1,m);