Matrix rows and columns swapping

I want to completely change rows and column simultaneously (please see the picture attached)
Is there a function which can do this?
Thanks,
Rakesh

2 Commenti

For anyone who is looking to swap an array:
Array = Array.';
btw sorry for reviving a dead thread.
That does not solve the user's problem at all. The user needs the upper left corner (a 1 in their data) to go to the middle, but using .' would leave the upper left corner exactly where it is.

Accedi per commentare.

Risposte (3)

There is no function that can do that simultaneously, at least not the first time.
For any given row and column exchange pattern, it is possible to pre-process the pattern so that doing the same exchange for multiple different arrays would take place simultaneously for that one matrix. Something like
temp = preprocess_exchange(rows_to_exchange, columns_to_exchange);
newA = A(temp);
newB = B(temp);
where preprocess_exchange is a function that would need to be written.

2 Commenti

I should correct myself: you can do this with indexing.
>> A = [1 2 3;4 5 6;7 8 9]
A =
1 2 3
4 5 6
7 8 9
>> A([2 1 3],[2 1 3])
ans =
5 4 6
2 1 3
8 7 9
Thanks. That works for me.

Accedi per commentare.

I don't think rows and column can be randomly changed simultaneously.
There should be at least 2 steps, like this:
% Input 3-by-3 matrix
A = reshape(1:9,3,3)';
% Randomize rows and columns
A = A(randperm(3),:);
A = A(:,randperm(3));
Franco Garcia
Franco Garcia il 24 Feb 2022
Modificato: Franco Garcia il 24 Feb 2022
You can actually do that easily with just proper indexing. According to the example in the attachment:
A=[1,2,3;4,5,6;7,8,9] % The input in your example
A = 3×3
1 2 3 4 5 6 7 8 9
B=A([2,1,3],[2,1,3]) % Your expected output
B = 3×3
5 4 6 2 1 3 8 7 9
Regards!

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