How to code this equation?

To improve the significance of the data, a comprehensive evaluation parameter was set in the experiment so that the average values of different sets of test data could be presented in a consistent manner:
1 (1).png
where n is the sample size, Yi is the result of testing on a certain sample, and Y_ is the average value.
How to code this equation?

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galaxy
galaxy il 5 Dic 2019

0 voti

This formula mean Y = sum of all Y(i) value with i = 1:n
I do not know what is Y(i) so can not write detai.
Please refer symsum

5 Commenti

Average gradient (AG). The AG reflects the ability to express the details of an image and can be used to measure the
relative clarity of the image. AG is formulated as:
This is the code AG
[dfdx,dfdy] = gradient(f) ;
M = (dfdx.^2+dfdy.^2)/2 ;
AG = mean(mean(M)) ;
But need help with this equation
To improve the significance of the data, a comprehensive evaluation parameter was set in the experiment so that the average values of different sets of test data could be presented in a consistent manner:
where n is the sample size, Yi is the result of testing on a certain sample, and Y is the average value.
How to code this equation?
never represents . Instead it represents which is easily expressed as mean(Y)
galaxy
galaxy il 5 Dic 2019
If Y is the average value, so the formular will as same as following.
formula.PNG
You can use the code from Walter Roberson.
Walter Roberson
Walter Roberson il 5 Dic 2019
Modificato: Walter Roberson il 5 Dic 2019
M = (dfdx.^2+dfdy.^2)/2 ;
should be
g = sqrt((dfdx.^2+dfdy.^2)/2);
AG = mean(g(:));
As well as the missing sqrt(), you should not be assigning to M as you are using M for an array size.
Alvin Alvin
Alvin Alvin il 5 Dic 2019
thanks Walter Roberson, give your answer will accept your answer for this question

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Più risposte (1)

y_bar = mean(Y);
or
y_bar = sum(Y)./length(Y);
Note: the second of those will malfunction if Y is a 2D array that has more columns than it has rows. The equation does not describe what should happen for 2D arrays, so what the "correct" output is for that case can be argued.

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