Wrong left and right assignment error
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    Arthur Moya
 il 9 Dic 2019
  
    
    
    
    
    Commentato: Jakob B. Nielsen
      
 il 9 Dic 2019
            Hi there, 
I have ellipsoids of different principal radii a b c and within these I attempt to quantify the number of smaller spheres with constant radii that I can fit into the ellipsoids and assess how the number of spheres changes with increasing ellipsoid axes.
The relationship of the counts and the size of the ellipsoids is as follows:
atom counts = 4/3*pi*a*b*c (2/0.0715) 
I am still new to matlab and I am struggling to get a proper expression to assess this.
The code below gives the following error:
Unable to perform assignment because the left and right sides have a different number of elements.
a = [3.4995 3.098 2.737 1.9185 2.1555 2.6865 2.0295 2.3715 1.111 2.1575 1.93 1.6605 1.884 1.9795 3.0115 1.2425 2.569 1.8575 1.4275 1.427 2.2905];
b = [2.29 2.807 2.1635 1.6945 1.1335 2.0845 1.7195 2.013 0.9385 1.68 1.7545 0.9175 1.0685 1.029 2.392 0.986 2.1365 1.576 1.0705 1.104 1.882];
c =[2.035 1.295 2.035 1.295 1.295 1.295 1.295 1.295 0.74 1.48 0.925 0.925 1.665 1.11 1.665 0.74 2.035 1.295 0.74 0.555 1.665];
f_pi= 4.1888;
ucellatoms= 2/0.0715;
for n= 1:1:100
    l(n) = n.*(a.*b.*c);
    Mean_diam(n) =(n.*(a+b+c)./3);
    atm_count = ucellatoms.*f_pi.*l;
    plot (atm_count,l,'o')
    nabc=l';
  mean_d = Mean_diam';
   atcounts=atm_count';
   Ex = [nabc,atcounts];
   plot(mean_d,atcounts, '*')
end 
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Risposta accettata
  Jakob B. Nielsen
      
 il 9 Dic 2019
        
      Modificato: Jakob B. Nielsen
      
 il 9 Dic 2019
  
      Your problem is that l(n) wants to place a single value into the array l in index n. But your a, b and c which you multiply with each other, are 1x21 arrays - as such the product of these is itself a 1x21 array. As such, you need to specify l (and Mean_diam as well) to be arrays themselves. The below will run, but I dont know if it will produce what you want it to :) 
a = [3.4995 3.098 2.737 1.9185 2.1555 2.6865 2.0295 2.3715 1.111 2.1575 1.93 1.6605 1.884 1.9795 3.0115 1.2425 2.569 1.8575 1.4275 1.427 2.2905];
b = [2.29 2.807 2.1635 1.6945 1.1335 2.0845 1.7195 2.013 0.9385 1.68 1.7545 0.9175 1.0685 1.029 2.392 0.986 2.1365 1.576 1.0705 1.104 1.882];
c =[2.035 1.295 2.035 1.295 1.295 1.295 1.295 1.295 0.74 1.48 0.925 0.925 1.665 1.11 1.665 0.74 2.035 1.295 0.74 0.555 1.665];
f_pi= 4.1888;
ucellatoms= 2/0.0715;
for n= 1:1:100
    l(:,n) = n.*(a.*b.*c);
    Mean_diam(:,n) =(n.*(a+b+c)./3); 
    atm_count = ucellatoms.*f_pi.*l;
    plot (atm_count,l,'o')
    nabc=l';
  mean_d = Mean_diam';
   atcounts=atm_count';
   Ex = [nabc,atcounts];
   plot(mean_d,atcounts, '*')
end 
4 Commenti
  Jakob B. Nielsen
      
 il 9 Dic 2019
				Well the first entry is row number, and l(:,1) = x simply means all rows in The first column. If you put a 2 row vector as x, The resulting l Will be a 2 by 1 array, and if your x is insteaf a 5000 row vector, your l Will be 5000 by 1. I hope that makes sense.
Più risposte (1)
  Steven Lord
    
      
 il 9 Dic 2019
        for n= 1:1:100
    l(n) = n.*(a.*b.*c);
When you execute that second line of code, n is a scalar (size 1-by-1.) The variables a, b, and c are 1-by-21 vectors. The result of evaluating n.*(a.*b.*c) is also 1-by-21. You're trying to stuff a 1-by-21 vector into one element of the variable l. That's not going to work; it doesn't fit.
What size do you want / expect the variables l and Mean_diam to be when this code finishes?
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