How to replace elements of matrix by elemts from array

k = 8;
x = 1:2500; % array 
h = 1:257;

newV = (0:length(x)-1).'*k+h;% matrix of indices

I have created matrix of indices, wich contains indexes of array x. Now I want to replace all elements of matrix by elemts from array x.

It should like this:

NewV = [x (1) x (2) x(3) ... ; x(9)... ; x(17)... ; x(25)... ]

Answer 1

[Akira Agata]

Basically, this task can be done by:

NewV = reshape(x,8,[])';

But in your case, length(x) can NOT be devided by k (=8). So you should adjust length(x) by padding/removing some elements.

[Dmitry Timofeev]

How I can remove this elements from array x?

[Dmitry Timofeev]

I've changed size of matrix 'newV'

clear; clc;
 
v = 1:257;
n = 100;
k = 8;
x = 1:2500;
h = 1:257;
n = length(1:8:length(x)-length(h));
NewV = (0:n-1).'*k + v;
NewV = reshape(x,8,[])';

But It still doesn't work.

How I should replace elements from array 'NewV' in this method:

NewV = [x (1) x (2) x(3) ... x(257); x(9)...x(265) ; x(17)... x(273); x(25)...x(281) ]

?

Answer 2

[Andrei Bobrov]

out = x(NewV);