interaction between matlab and SAP2000?
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Hi,
I want to call CSI SAP2000 in matlab using the SAP2000 OAPI, but i can't find any documentation on how to do that. The CSI documentation includes examples on how to do it in Visual basic only. Any help with finding some reference or tutorial would be highly appreciated.
Thanks
3 Commenti
Tan Nguyen
il 16 Nov 2020
Hi,
I also face some problem about it:
ConstraintDef.SetDiaphragm
GroupDef.Count
etc.
I cannot iniciate any code with "Def" as seen before.
Could anyone help?
Reza
il 26 Mag 2021
Mohammad Sadegh Eshaghi
il 27 Set 2023
Risposta accettata
Più risposte (2)
There is a toolbox,called SM,that can call SAP2000(CSiBRiDGE) in MATLAB,
Follow the below link to make connection between SAP2000(CSiBRiDGE) and MATLAB
5 Commenti
Daniel
il 26 Giu 2022
Modificato: Walter Roberson
il 27 Set 2023
Hi,
I am trying to open a sap2000.v21 model in MATLAB. I'm using the SM Toolbox Version 6.0.4 Instructions but it gives me an error in the syntax. I show you the code an the error. I'm sorry for my english.
Any help would be really appreciated.
Thanks
%clean up the workspace of matlab
clc;
clear;
%determine the type of application and its version
SM.App( 'sap' );
SM.Ver( '21' );
%create Sap2000 object
APIDLLPath ='C:\Program Files\Computers and Structures\SAP2000 21\SAP2000v1.dll';
ProgramPath ='C:\Program Files\Computers and Structures\SAP2000 21\SAP2000.exe';
[ Sobj ] = SM.Helper.CreateObject( ProgramPath,APIDLLPath );
%create SapModel object
[ Smdl ]=SM.SapModel();
%start Sap2000 application
SM.ApplicationStart;
%initialize model
ret = SM.InitializeNewModel;
%open an existing file
ModelName = 'Example 1-019a.sdb';
ModelPath = fullfile(pwd,'Analysis Examples',ModelName);
ret = SM.File.OpenFile(ModelPath);
%close Sap2000
SM.ApplicationExit (false);
Undefined function 'contains' for input arguments of type 'char'.
Error in SM.Helper.CreateObject (line 8)
Error in Ex_SM_File_OpenFile (line 10)
[ Sobj ] = SM.Helper.CreateObject( ProgramPath,APIDLLPath );
Walter Roberson
il 26 Giu 2022
Daniel, which MATLAB version are you using? contains was added about R2016b
Daniel
il 26 Giu 2022
I am using Matlab Version 2015a
Walter Roberson
il 26 Giu 2022
The SM code you found is not compatible with your version of MATLAB.
However you might be able to get away with
function found = contains(base, pattern)
found = ~isempty(strfind(base, pattern)) ;
Daniel
il 2 Lug 2022
Thank's a lot!
Mohammad Sadegh Eshaghi
il 27 Set 2023
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