Comparing terms in a character array

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Hey,
I have character array with terms solve= (B*C) + (A*~C), I am comparing terms from table to determine if it exist exact in the character array. I tried.
if strcmp(solve,'A*C')
do nothing
else
" I would to add the term ('A*C') from the if statement into solve"
end
Can anyone assist me in matching if the exact term exist in the array & if not I would to add it to the existing character array.
Thanks.
  2 Commenti
KSSV
KSSV il 10 Feb 2020
What is solve? Is it a string?
vedesh Mohit
vedesh Mohit il 10 Feb 2020
Solve the character array

Accedi per commentare.

Risposta accettata

J. Alex Lee
J. Alex Lee il 10 Feb 2020
If it is truly a "character array" and you want exact matches only, you can use the findstr() command, which will return empty if not found
expr = '(B*C) + (A*~C)'
newterm = '(A*C)'
if isempty(findstr(expr,newterm))
expr = [expr ' + ' newterm]
end
If your expression is a string as KSSV was asking, you can do
expr = "(B*C) + (A*~C)"
newterm = '(A*C)'
if ~expr.contains(newterm)
expr = expr + " + " + newterm
end

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