Numeric matrix to string matrix
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Emmanuel Matata Bili Bili
il 7 Mar 2020
Commentato: Emmanuel Matata Bili Bili
il 28 Mar 2020
Hi,
Newbie here, need some assistance in solving this problem.
Input is a numeric matrix x (any dimension). Return value is a string matrix.
The rules are :
If the x <= 30, then return “small”, if 30 < x <= 50, then return “medium”, otherwise return “high”
When I run the first "If" statement by itself I get x = "low" "low" "low" "low"
Then when I add the elseif statement I get nothing. Matlab simply ouputs the same results.
It seems like the code is only looking at the first row of my matrix. It also seems that it's considering 45 as less than 30.
I appreciate all the help in advance. I'm new learner, slowly learning programming.
First if statement only.
A = [1 2 45 4 ; 5 6 45 8];
for i = 1:length(A);
if A(i) <= 30
x(i)= "low"
end
end
>>
x =
1×4 string array
"low" "low" "low" "low"
elseif statement
A = [1 2 45 4 ; 5 6 45 8];
for i = 1:length(A);
if A(i) <= 30
x(i)= "low"
elseif 30 > A(i) & A(i)<= 50
x(i) = "medium"
end
end
>>
x =
1×4 string array
"low" "low" "low" "low"
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Risposta accettata
Ameer Hamza
il 7 Mar 2020
Modificato: Ameer Hamza
il 7 Mar 2020
x = [5 15 25;
35 45 55;
65 75 85];
result = strings(size(x));
result(x<=30) = "small";
result(x>30 & x<=50) = "medium";
result(x>50) = "large";
The result is
result =
3×3 string array
"small" "small" "small"
"medium" "medium" "large"
"large" "large" "large"
Più risposte (1)
Guillaume
il 7 Mar 2020
The easiest way, by far, to do this in matlab is:
A = [1 2 45 4 ; 5 6 45 8]; %demo data
result = discretize(A, [-Inf, 30, 50, Inf], ["low", "medium", "high"])
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