Azzera filtri
Azzera filtri

How can I plot multiple iteration loglog graphs.

3 visualizzazioni (ultimi 30 giorni)
N0 = 1*10.^9;
n = 3;
T=365*24*3600;
Table = cell(n, 4);
t = logspace(1, 7);
A = logspace(-22,-1);
ylabel('Activity /s^.-1');
xlabel('t');
set(gca,'xscale','log')
L(1) = 4.979*10.^-18;
L(2) = 3.329*10.^-7;
L(3) = 2.874*10.^-5;
for i=2:n
Bsum=0;
for t = 1:1*10.^5:T
Prod1 = 1;
for l = 1:i-1
Prod1 = Prod1*L(l);
end
for j = 1:i
Prod2 = 1;
for k = 1:i t
if k ~= j
Prod2 = Prod2*(L(k) - L(j));
end
end
Sum = Ssum+exp(-L(j)*t)/Prod2;
end
F = Sum*Prod1*N0;
A = Sum*L(i);
Table(i, :) = {i t F A };
fprintf('%d %d %d %d\n', Table{i, :, :});
end
end
My Scipt needs to output graphs for each iteration of i in terms of A against t, at the moment it will do it to i=3 but if I need to more I would like it to automatically plot the graphs like the subplot command.
Currently my code for my graph only outptus the whole of the iteration from 1:3 rather than each iteration
Activity = logspace(-22,-1);
loglog(A,t,'-o')
line(A, t)
Any help will be great!

Risposta accettata

Sindhu Karri
Sindhu Karri il 27 Mar 2020
You can try using nexttile which is similar to subplot
By using nexttile, loglog inside the for loopyou will be able to plot the graph of (A,t) for each iteration.
Refer to the below link:
  1 Commento
Alex Manuel
Alex Manuel il 28 Mar 2020
I've run into a problem where only my last value is used, how would I go about plotting each A at each t step for a specific iteration?
i t A Sum
3 310 8.251044e-09 2.371350e-13
3 311 8.330961e-09 2.394318e-13
3 312 8.411392e-09 2.417434e-13
3 313 8.492338e-09 2.440698e-13
3 314 8.573802e-09 2.464111e-13
3 315 8.655785e-09 2.487673e-13
3 316 8.738288e-09 2.511384e-13
It looks like this, where only the very last value is used on the graph.
i t A Sum
3 316 8.738288e-09 2.511384e-13

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