How to compute the derivative of the neural network?
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Hi,
Once you have trained a neural network, is it possible to obtain a derivative of it? I have a neural network "net" in a structure. I would like to know if there is a routine that will provide the derivatives of net (derivative of its outputs with respect to its inputs).
It is probably not difficult, for a feedforward model, there is just matrix multiplications and sigmoid functions, but it would be nice to have a routine that will do that directly on "net".
Thanks!
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Più risposte (4)
Filipe
il 20 Ott 2012
0 voti
1 Commento
Greg Heath
il 24 Ott 2012
You can try to make life easier by doing the pre and postprocessign yourself before and after training.
trevor
il 7 Nov 2013
0 voti
Hi Filipe,
Could you possibly share your code for computing the partial derivative of the ANN, or provide some info on the steps you used? That would be immensely useful!
Thanks, Trevor
Muhammad Saif ur Rehman
il 5 Apr 2019
0 voti
Hi Filipe,
Can you share your code for computing the partial derivative of defined cost function w.r.t input?
Regards Saif
soo-choon kang
il 14 Ago 2021
0 voti
net1 = fitnet(3);
net1 = train(net1,x',y');
% normalize x
nx = (x-net1.input.processSettings{1,1}.xmin)*net1.input.processSettings{1,1}.gain+net1.input.processSettings{1,1}.ymin;
h = tanh(net1.b{1}+net1.IW{1}*nx'); % h = [3xn] IW{1} = [3x1] x' = [1xn]
ny = net1.b{2}+net1.LW{2,1}*h; % y = [1xn] LW{2,1} = [1x3]
% de-normalize y
ypredict = (ny-net1.output.processSettings{1,1}.ymin)/net1.output.processSettings{1,1}.gain+net1.output.processSettings{1,1}.xmin;
% above ypredict is equivalent to predict(net1,x)
% derivative of nn at normalized scale
dnydnx = sum(net1.LW{2,1}'.*net1.IW{1}.*(1-h.*h),1)'; % dyy = [1xn] h'*h = [nxn]
% derivative of nn at real scale
dydx = dnydnx*net1.input.processSettings{1,1}.gain/net1.output.processSettings{1,1}.gain;
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