bisection method with log

if a=15

b=60

Sy=1070

p= 700

how can i find c using bisection method

P= (Sy/3)*(1-(c^2/b^2)+log(c^2/a^2))

[Ameer Hamza]

This seems like a homework question. What have you already tried? Here are some examples:

https://www.codewithc.com/bisection-method-in-matlab/

https://www.mathworks.com/matlabcentral/fileexchange/33748-bisection-method

https://www.mathworks.com/matlabcentral/fileexchange/28150-bisection-method-root-finding

Answer 1

[David Hill]

Once you graph your function, you see there are 4 roots. Using the bisection method to find the numerical roots should now be easy.

a=15;
b=60;
Sy=1070;
p=700;
c=-150:.1:150;
y=@(c)(Sy/3)*(1-(c.^2/b^2)+log(c.^2/a^2))-p;
plot(c,y(c));

[Mohamad Mourad]

Thank you very mush , it is very useful