How do i use fimplicit function for a graph?

4 visualizzazioni (ultimi 30 giorni)
dunphy
dunphy il 19 Apr 2020
Modificato: madhan ravi il 20 Apr 2020
How do i do this using fimplicit function? I tried it and a heart comes out in a graph. I would just like to know if there should be and x and y element on this kind of problem? For instance y vs x?
This is what i first did. Do i put elements to recognize the x and y? What should be my independent and dependent variable?
  1 Commento
Walter Roberson
Walter Roberson il 19 Apr 2020
you used the square root of x squared, but the question requires the cube root of x squared.

Accedi per commentare.

Risposte (1)

madhan ravi
madhan ravi il 19 Apr 2020
Modificato: madhan ravi il 20 Apr 2020
(x.^2).^(1/3) % edited after sir Walter’s comment
  2 Commenti
Walter Roberson
Walter Roberson il 20 Apr 2020
The question does not involve any square roots, only a cube root.
(x.^2).^(1/3)
Or alternately, because we can predict that x^2 will be real-valued and non-negative:
nthroot(x.^2, 3)
madhan ravi
madhan ravi il 20 Apr 2020
Ah thank you sir Walter.

Accedi per commentare.

Categorie

Scopri di più su Networks in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by