Sequential, row-wise reshape of an M–by–N matrix to form a 1–by–N vector

7 visualizzazioni (ultimi 30 giorni)
Dumb question. Let's say I have the following matrix:
A = [2 1
4 3
6 5
8 7
10 9];
Is there a way to use circshift(), some combinaton of circshift(), reshape(), transpose(), etc, or other set of functions to obtain the following.
A = somefun(A) % or combinaton of functions and operations
A =
2 1 4 3 6 5 8 7 10 9
I could easily obtain this result with with a for loop, but I am wondering if there is another means to go about this. Notice that the rows are sequentially 'stacked' along the N–dimension. The question could similarly be phrased in terms of columns to produce an M–by–1 column vector.
Edit: Accidental, premature submit.

Risposta accettata

Stephen23
Stephen23 il 22 Apr 2020
reshape(A.',1,[])

Più risposte (0)

Categorie

Scopri di più su Shifting and Sorting Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by