Probability of an event

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Kendall Donahoe
Kendall Donahoe il 28 Apr 2020
Modificato: Kendall Donahoe il 28 Apr 2020
thankyou

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David Hill
David Hill il 28 Apr 2020
You could loop through this many times to attempt to get a better answer.
x=randi(100,100000000,5);
m=[20,63,78,11,45];
s=zeros(100000000,1);
for k=1:5
s=s+double(x(:,k)==m(k));
end
proB=sum(s>=3)/100000000;

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