Process a sequence of files
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EDIT2
I have a question about how can I process a sequence of files. What I've done is extract some information of one file (49271) to write it on a new one ('text'). The problem is I don't know how to do it with a sequence of txt files and also, how can write it on 'text.txt' the result 'line by line'.
myPath = 'C:\EX\';
a= dir (fullfile(myPath,'*.DIM'));
fileNames = { a.name };
for k = 1:length(fileNames)
newFileName = [fileNames{k}(1:2) fileNames{k}(4:6) '.txt'];
movefile([myPath fileNames{k}], [myPath newFileName]); % rename the files
end
`% extract information
fid = fopen('49271.txt', 'r');
for i = 1:18
m = fgetl(fid);
end
result2 = m([12:19]);
fid = fopen('49271.txt', 'r');
for i = 1:30
p = fgetl(fid);
end
result3 = p([12:19]);
fid = fopen('49271.txt', 'r');
for i = 1:31
q = fgetl(fid);
end
result4 = q([12:20]);
fid = fopen('49271.txt', 'r');
for i = 1:19
r = fgetl(fid);
end
result5 = r([12:20]);
% copy information in a new variable (of one line)
load('text.txt');
text= {newFileName, result2, result3, result4, result5}
I'm trying with the following code but I don't know how to write it:
filePattern=fullfile( myPath,'*.txt');
txtFiles= dir(filePattern);
for k = 1:length(txtFiles)
baseFileName=txtFiles(k).name;
fullFileName= fullfile(myPath,baseFileName);
fid=fopen('filePattern', 'r');
for i = 1:18
m = fgetl(fid);
end
result2 = m([12:19]);
end
Thanks in advance!
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Risposta accettata
Pedro Villena
il 30 Ott 2012
filePattern=fullfile( myPath,'*.txt');
txtFiles= dir(filePattern);
for k = 1:length(txtFiles.names),
fullFileName=fullfile(myPath,txtFiles(k).name);
fid=fopen(fullFileName, 'r');
for i = 1:18
m{i} = fgetl(fid);
end
result2 = m{12:18};
end
Più risposte (1)
Walter Roberson
il 30 Ott 2012
It is tricky to skip characters in text files without reading them. It is much easier to read the text and throw away what you do not want.
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