& operator without if

Why this rutine:

[0 0]<[1 1] & [0 0]<[-1 1]

return:

[0 1]

how work conditional operator & without if?

[Stephen23]

These are the two inputs that you provided to the element-wise & operator:

>> [0 0]<[1 1]
ans =
  1  1
>> [0 0]<[-1 1]
ans =
  0  1

Are you uncertain how AND logic works? What do you expect the & operator to do?

[daniel molina]

yes, I want to know how work AND in this case, that result this answer

>>[0 0]<[1 1] & [0 0]<[-1 1]

ans =

0 1

[James Tursa]

& is the an element-wise operator.

Answer 1

[Steven Lord]

The & operator is an elementwise operator. Just like the + operator will add corresponding elements of its inputs when given two vectors of the same size:

x = [1 2 3];
y = [4 5 6];
z = x + y % z(1) = x(1) + y(1), z(2) = x(2) + y(2), z(3) = x(3) + y(3)

The & operator will take the and of the corresponding elements of its inputs.

a = [true false true];
b = [true true false];
c = a & b; % c(1) = a(1) & b(1), c(2) = a(2) & b(2), c(3) = a(3) & b(3)

The & operator with two scalars as input returns true if both its inputs are non-zero and false otherwise.

[ true &  true; ... % true
  true & false; ... % false
 false &  true; ... % false
 false & false]     % false