Sorting matrix with specifications for the order

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Jean
Jean il 19 Nov 2012
Hi,
I have a certain matrix with n rows and 3 columns. I want to sort it according to the sums of the squares of its columns.
For example, let's say my matrix is
0 0 1
0 0 2
1 1 1
Since for the second row we have: 0^2+0^2+2^2 = 4, which is larger than the 3rd row: 1^2+1^2+1^2 = 3. In such a case, I want my matrix to look like:
0 0 1
1 1 1
0 0 2
Thank you for your help, it is very appreciated !

Risposte (2)

Azzi Abdelmalek
Azzi Abdelmalek il 19 Nov 2012
A=[0 0 1;0 0 2;1 1 1];
[~,idx]=sort(sum(A.^2,2))
out=A(idx,:)
  1 Commento
Jan
Jan il 19 Nov 2012
This is faster than the arrayfun approach, but of course this matters for larger matrices only.

Accedi per commentare.


Yowh
Yowh il 19 Nov 2012
Here .. I think this will work ..
A = [0 0 1;0 0 2;1 1 1;0 0 0];
ans = sortrows(A, [3 2 1])

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