Why am I getting an indices error?

2 visualizzazioni (ultimi 30 giorni)
clc;
clear;
data = readtable('A_minute.xlsx');
% step 2: store date and time data as a datenum (DaT) and then convert to datetime (t)
% summer: t(2:102241)
DaT = datenum(data.Var1);
t = datetime(DaT, 'ConvertFrom','datenum');
TimeofDay = timeofday(t(2:102241));
TimeofDay = ceil(TimeofDay,'minute');
[UniqueTimeSteps,~,pos] = unique(TimeofDay);
UniqueTimeSteps = UniqueTimeSteps(2:end);
pos =pos -1;
pos(pos==0) = 24;
% step 3: store the other columns from the excel data file
AptA = data(:,4);
AptA = table2array(AptA);
AptA = AptA(1:102241);
% step 4: for loop extracting the hour and indexing it through for weekday versus weekend
Consumption_Weekday = zeros(1,length(UniqueTimeSteps));
Consumption_Weekend = zeros(1,length(UniqueTimeSteps));
wd = weekday(t) > 1 & weekday(t) < 7;
for i = 1:length(UniqueTimeSteps)
idx = (pos == i & wd);
Consumption_Weekday(i) = mean(AptA(idx));
idx = (pos == i & (~wd));
Consumption_Weekend(i) = mean(AptA(idx));
end
MinuteValue= UniqueTimeSteps;
% step 5: plot
figureA = figure;
plot(MinuteValue,Consumption_Weekday,'-b');
hold on
plot(MinuteValue,Consumption_Weekend,'-r');
ylim([0.2 0.7]);
xlabel('Time'), ylabel('Electric Demand (kW)'), ...
title('Unit A - Average Aggregated HVAC Electric Demand (kW)'), ...
legend('Weekdays','Weekends')
Matrix dimensions must agree.
Error in A_minute_wk (line 30)
idx = (pos == i & wd);
  2 Commenti
Walter Roberson
Walter Roberson il 8 Giu 2020
You did not indicate which line was causing the problem, but observe that
idx = (A_t.Minute == MinValue & weekday(A_t) > 1 & weekday(A_t) < 7);
could potentially match several entries, so AptAs(idx) might be multiple values (or no values?), but you expect it to be a scalar.
Fatemah Ebrahim
Fatemah Ebrahim il 8 Giu 2020
I just edited the question, please see above

Accedi per commentare.

Risposta accettata

Walter Roberson
Walter Roberson il 8 Giu 2020
[UniqueTimeSteps,~,pos] = unique(TimeofDay);
pos will be a vector with as many entries as TimeofDay has.
pos =pos -1;
pos(pos==0) = 24;
Those do not change the size of pos.
t = datetime(DaT, 'ConvertFrom','datenum');
TimeofDay = timeofday(t(2:102241));
TimeOfDay will be exactly 102240 elements long (or else you would have gotten an error at that step).
TimeofDay = ceil(TimeofDay,'minute');
That did not change the size of TimeOfDay.
So we know that TimeOfDay will have 102240 elements, and since pos is the same size, pos will have 102240 elements.
wd = weekday(t) > 1 & weekday(t) < 7;
We do not know (without knowing the size of input) how large t is. But we can guarantee that it is larger than TimeOfDay, because TimeOfDay is derived from something that starts at element 2 of t. t might potentially end at 102241, but that would make it 1 element larger than TimeofDay.
idx = (pos == i & wd);
As described above, those are certain to be different sizes.

Più risposte (0)

Categorie

Scopri di più su Dates and Time in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by