how can I make in Simulink ∫ dt?

Hi, how can I make in Simulink ∫ dt? In time domain, not Laplace domain.
Thank you:)

Risposte (1)

Andreas Goser
Andreas Goser il 14 Dic 2012
Modificato: Andreas Goser il 14 Dic 2012

0 voti

The whole concept of Simulink is time based simulation. You might be confused by the look of the blocks and the transfer functions are displayed like 1/s or 1/s-1 etc.
So just use the integrator block and you are fine.

5 Commenti

ionut
ionut il 14 Dic 2012
I know that I can use 1/s but my teacher told me to not use 1/s. He said to me that I can find ∫ dt in Simulink Lybrary Browser. I have to simulate a DC motor. And one of blocks is (1/La)*∫ dt. Where La is known. Could you help me please?:)
I can't help with that. I can only speculate what your teacher might think. There are blocks that display the integral symbol, like the "Integrator Limited" block. You need to ask the teacher.
ionut
ionut il 14 Dic 2012
I asked today him and I can remember that he told me that I can replace 1/s with a MUX+I can't remember what other blocks. It's that possible?
I do not see any relationship between an integral operation and a signal infrastructure block. This is very confusing. Probably both of you call into Technical Support to sort out things together?
ionut
ionut il 22 Dic 2012
I spoke with my teacher and I'll use the 1/s block. Thank you very much for you support.

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il 14 Dic 2012

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