cycle for integrating vector sections
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Hello! I have a vector that I need to integrate over the sections, the length of the section is 3
% now I use such a loop, but it gives me 900 answers, but should 300
for i=1:length(Fi)
x=Fi(i:i+2); % +2 I need to integrate sections (3 values per section)
LayerDepstep(i)=trapz(x);
end
% x=900 % 300
% Fi vector 1:900 %
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Risposte (1)
Alan Stevens
il 21 Lug 2020
Perhaps you should have something like:
for i=1:4:length(Fi)-2
x=Fi(i:i+2); % +2 I need to integrate sections (3 values per section)
LayerDepstep(floor(i/4)+1)=trapz(x);
end
2 Commenti
Alan Stevens
il 21 Lug 2020
It does what you appeared to be asking for, i.e. reduces the number of sections by a factor of 3. What problem remains?
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