Unique changing order(unique output values are reshuffled)
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shaz
il 18 Dic 2012
Commentato: Stephen23
il 17 Gen 2018
i have cell array with data like '2/6/2009','2/6/2009','2/6/2009','2/6/2009','2/7/2009',,'2/7/2009','2/7/2009','2/8/2009','2/8/2009','2/8/2009'
if i make use of unique to get only unique values the order is getting reshuffled
getting output like : '2/8/2009','2/6/2009','2/7/2009'
Desired output format: '2/6/2009','2/7/2009','2/8/2009'
1 Commento
Stephen23
il 17 Gen 2018
>> C = {'2/6/2009','2/6/2009','2/6/2009','2/6/2009','2/7/2009','2/7/2009','2/7/2009','2/8/2009','2/8/2009','2/8/2009'};
>> D = natsort(unique(C));
>> D{:}
ans = 2/6/2009
ans = 2/7/2009
ans = 2/8/2009
But the best solution is to change the date format for an ISO 8601 date format, which sort correctly into chronological order when you do a character sort. Once you start using ISO 8601 date formats you simply avoid all of these trivial problems.
Risposta accettata
Muruganandham Subramanian
il 18 Dic 2012
b={'2/6/2099','2/6/2099','2/6/2099','2/6/2099','2/7/2099','2/7/2099', '2/7/2099','2/8/2099','2/8/2099','2/8/2099','2/10/2099','2/10/2099', '2/12/2099'};
c=datevec(b);
c(:,4:6)=[];
c(:,4)=c(:,1);
c(:,1)=[];
d=num2str(c);
d=cellstr(d);
d=unique(d)
Check this above code. But it's not effective way to do..here In unique(), it's not chosing in random way, it considers the data of first,which is sorted minimum(i.e. '10' is first than '6').
4 Commenti
Andrei Bobrov
il 19 Dic 2012
M = datevec(b,'mm/dd/yyyy');
[Muq, ii] = unique(M,'rows','first');
out = b(sort(ii));
Più risposte (4)
Muruganandham Subramanian
il 18 Dic 2012
Modificato: Muruganandham Subramanian
il 18 Dic 2012
>>b={'2/6/2009','2/6/2009','2/6/2009','2/6/2009','2/7/2009','2/7/2009','2/7/2009',
'2/8/2009','2/8/2009','2/8/2009'};
>> c=unique(b)
>> c =
'2/6/2009' '2/7/2009' '2/8/2009'
Are you expecting this?
Sebastian
il 17 Gen 2018
I know it's a bit late for an answer, but maybe it helps others. If you want to preserve the order of the input of 'unique', you can use the second return parameter. Like that it works for arbitrary data (i.e. strings and numerals, basically every data type 'unique' supports):
a = {'2/6/2009' '2/6/2009' '2/6/2009' '2/7/2009' '2/7/2009' '2/7/2009' '2/8/2009' '2/8/2009' '2/8/2009'};
[~, uIdx] = unique(a);
a(sort(uIdx))
This snippet does the following: Store the indices of the unique elements of 'a' in 'uIdx'. Then return the elements of 'a' from the first to the last using 'sort'.
1 Commento
Jan
il 17 Gen 2018
The problem of shaz was, that he wanted a specific numerical order, in which '6' appears before '10'. Therefore the data must be converted from string to double, such that the sorting works.
Steven Lord
il 17 Gen 2018
Convert your date data into a datetime array, then call unique (with or without the 'stable' flag) on the datetime array.
C = {'2/6/2009','2/6/2009','2/6/2009','2/6/2009','2/7/2009','2/7/2009', ...
'2/7/2009','2/10/2009','2/8/2009','2/8/2009'};
D = datetime(C, 'InputFormat', 'MM/dd/uuuu')
unique(D)
unique(D, 'stable')
For purposes of this example I assumed your dates were days in February 2009. If they were the second of each month from June through October (without September) of 2009 swap the MM and dd sections of the InputFormat parameter.
1 Commento
Stephen23
il 17 Gen 2018
"For purposes of this example I assumed your dates were days in February 2009. If they were the second of each month from June through October (without September) of 2009 swap the MM and dd sections of the InputFormat parameter."
Or avoid this pointless and confusing ambiguity entirely by using ISO 8601 dates.
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