How to get z for different x

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Atom
Atom il 18 Dic 2012
x = [-2:0.1:2];
z=x.*(1-x).*(2-x).*(4-x)/((6-x)-(1-x).*(x-7));
I am getting error. Please correct my problem.
  2 Commenti
Thomas
Thomas il 18 Dic 2012
what error are you getting? what answer do you expect?
Atom
Atom il 18 Dic 2012
Modificato: Atom il 18 Dic 2012
There are 41 values of x and for each x I need one z. I am not getting this. I am getting only one value of z (=-2.1203).

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Risposta accettata

Wayne King
Wayne King il 18 Dic 2012
Modificato: Wayne King il 18 Dic 2012
x = [-2:0.1:2];
z = x.*(1-x).*(2-x)./((6-x).*(x-7));
You just forgot a ./
Now you should have a vector
x = [-2:0.1:2];
z = x.*(1-x).*(2-x)./((6-x).*(x-7));
plot(x,z)

Più risposte (2)

Thomas
Thomas il 18 Dic 2012
x = [-2:0.1:2];
z=x.*(1-x).*(2-x).*(4-x)./((6-x)-(1-x).*(x-7))
You missed the . before the division to do element by element division

Daniel Shub
Daniel Shub il 18 Dic 2012
Presumably you want to use ./ instead of /, just like you are using .* instead of *

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