Info
Questa domanda è chiusa. Riaprila per modificarla o per rispondere.
What is the problem in these code?
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hello friends, I have a code like this:
for x=1:50
Nrows=size(orj_matr,1)
new_matr=randperm(Nrows)
new_matr=new_matr(1:50)
a(:,:,x)=orj_matr(new_matr,:)
end
When I wrote this codes to MATLAB, I have 50 different (50 rows-10 columns) matrices. Like this:
a(:,:,1) , a(:,:,2), a(:,:3), …………a(:,:,50)
And I want to calculate f1 and f2 for these 50 different matrices. When I wrote like this there was an error saying “Indexing must appear last in an index expression”.
f1=sum(a(:,:,x) (:,1:2:end),2);
f2=sum(a(:,:,x) (:,2:2:end),2);
What is the mistake in these codes? Please help me...
1 Commento
Jan
il 19 Dic 2012
Modificato: Jan
il 19 Dic 2012
It would be useful if you explain, what the the expression "a(:,:,x) (:,1:2:end)" should do. As long as it is no valid Matlab syntax, a suggestion for improvement requires guessing what you want to achieve. And an answer based on guesses can be worse than no answer.
Risposte (2)
Jürgen
il 19 Dic 2012
Modificato: Jürgen
il 19 Dic 2012
Hi,
sum(a(:,:,x) (:,1:2:end),2); is not correct , I think What do you want to do there? '(:,1:2:end)' is referring to the index and it put at the right place regards,J
3 Commenti
José-Luis
il 19 Dic 2012
I would recommend you read up on indexing.
a(:,:,x) (:,1:2:end)
is not a valid expression. I am guessing that what you want is something along the lines
squeeze(sum(a(:,1:2:end,:),2))
Also, please edit your code to make it more readable. That might attract more answers.
Questa domanda è chiusa.
Vedere anche
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!