mean value of polynominal function
11 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Christoph Thorwartl
il 24 Lug 2020
Commentato: Christoph Thorwartl
il 24 Lug 2020
Given is a polynomial function k. I would like to calculate the mean value of the function between two points (x1, x2).
This solution is too imprecise for my purpose.
mean = (polyval(k,x2) + polyvalk,x1))/2
I would be very grateful for any feedback.
1 Commento
Risposta accettata
Più risposte (1)
John D'Errico
il 24 Lug 2020
Modificato: John D'Errico
il 24 Lug 2020
The average value of a function over some interval is just the definite integral of the function, then divided by the length of the interval. Goes back to basic calc.
Since you are talking about using polyval, then I assume the polynomial is in the form of coefficients, appropriate for polyval. As an example, consider the quadratic polynomial x^2 - x + 2, on the interval [1,3].
k = [1 -1 2];
x12 = [1 3];
format long g
>> diff(polyval(polyint(k),x12))/diff(x12)
ans =
4.33333333333333
If you want to verify the result:
syms x
K = x^2 - x + 2;
int(K,x12)/diff(x12)
ans =
13/3
They agree, as they should.
In both cases, this yields the exact result for that polynomial, not an approximation. Exact at least to within the limits of floating point arithmetic.
If you want a reference, this should do:
2 Commenti
Vedere anche
Categorie
Scopri di più su Calculus in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!