How to sort a vector according to another vector

I have a desired vector u of order 1x6 i.e. one row and 6 columns. Likewise I generate another random vector of same size 1x6. The arrangement of elements in that random vector is varying. Now I want to get such a random number which is nearly the same as my u vector. And also I want to re-arrange the elements of that random vector according to the arrangment of my u vector. How can I do that?

[Stephen23]

Duplicate:

https://www.mathworks.com/matlabcentral/answers/602632-how-to-get-a-random-vector-whose-elements-arrangement-is-the-same-as-that-of-my-desired-vector?s_tid=prof_contriblnk

Answer 1

[Ameer Hamza]

What about adding random values to the first vector

u = [2 1 3 6 4 2];
v = u + rand(size(u))*0.1;

Result

>> u
u =
     2     1     3     6     4     2
>> v
v =
    2.0032    1.0211    3.0612    6.0179    4.0297    2.0483

[Sadiq Akbar]

Thank you very much dear Ameer Hamza for your prompt response. No I don't mean like that. Actually the randome vector is comming from a function in which (1) the arragment of elements may not be the same as that of u. (2) in which value of elements may be any real values. (3) size of both of u and random vector is same. Suppose I get a random number in which values of the elements are nearly equal to values of u vector but the arrangement of elements in this random vector is not the same as my u vector. I want to re-arrange this random vector according to my u vector.