remove rows from a matrix on a specific condition

I want to remove rows from a matrix when a specific condition is satisfied.

For example, lets as assume that I have the following 5x5 matrix :

A=   [ 5 3 3 1 4
       6 6 3 1 0
       6 2 2 2 0
       4 2 3 2 0
       1 1 1 1 2 ]

and I want to delete the rows of this matrix when the elements of the 5th column are equal to 0, so I will be left with the first and last row as an outcome:

A=   [ 5 3 3 1 4
       1 1 1 1 2 ]

Thanks

[Dimitris]

Just to make clear there are ; for every 5 elements in the example to separate the rows, I hope it is clear, sorry about that

Answer 1

[Daniell Algar]

Try

A= [ 5 3 3 1 4; 6 6 3 1 0; 6 2 2 2 0; 4 2 3 2 0; 1 1 1 1 2 ]
A(A(:, 5)== 0, :)= []

[Constantin]

I have tried to do this for the table variable type, but I get the following error message:

Undefined operator '~=' for input arguments of type 'table'

It seems that logical indexing doesn't work in the same way for table variables. What would be an equivalent procedure?

[Raghu Vamsi]

What if the 0 is not exactly in the 5th Column but random in cells, then how to solve the same issue?

[Jona Gladines]

@Raghu Vamsi, If still needed, repeat for every column. As it wil only remove the rows with a 0 in that specific column.