Removing rows in a matrix

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Chris Dan
Chris Dan il 19 Ott 2020
Commentato: Ameer Hamza il 20 Ott 2020
I have this matrix, called A matrix. I am attaching the file with the question. Also the picture of some of its data values
I need to remove some of its rows in a loop. I want to keep rows 1,2 then remove 3,4,5,6, keep 7,8,then remove 9,10,11,12, keep 13,14.. like this it goes on.keep 2 remove 4 rows.
Does anyone know?

Risposta accettata

Ameer Hamza
Ameer Hamza il 19 Ott 2020
Try this
n = size(Identify_3);
idx = (mod((1:n)-1, 6)+1) <= 2;
Identify_3 = Identify_3(idx, :);
  3 Commenti
Ameer Hamza
Ameer Hamza il 20 Ott 2020
You can do it like this
D = C([1 48:48:end], :)

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Più risposte (2)

Bjorn Gustavsson
Bjorn Gustavsson il 19 Ott 2020
Modificato: Bjorn Gustavsson il 19 Ott 2020
If you can determine/calculate all rows you want to remove at once it is best to do the re-sizing of the array at once, instead of row-by-row (if I've understood this right, the reallocation-operation is the main argument to not automatically and incrementally grow arrays, ought to be similar for shrinking.):
idx2remove = [];
for i1 = 1:size(A,1)
if some_conds(A(i1,:))
idx2remove = [idx2remove,i1];
A(idx2remove,:) = [];
Ah, if you have to remove rows [3,4,5,6]+6*n then something like this should work:
idx2remove = 1:size(A,1);
idx2remove = reshape(idx2remove,6,[]);
idx2remove = idx2remove(3:end,:);
A(idx2remove(:),:) = [];
If this doesn't work out because your A doesn't have a multiple of 6 rows, then you'll have to modify the creation of the remove-array a bit. You could also go for creating an array with row-indices to keep and do:
A = A(idx2keep,:);

KSSV il 19 Ott 2020
Let A be your data. It seems every four rows have real value of complex number very less. We can use keep these rows.
idx = real(abs(A(:,1)))<=10^-10 ; % this will give indices of what you want to keep
iwant = A(idx,:)


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