Complex number and degrees

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john
john il 18 Feb 2013
Hi,
result of code
x=3*cos(pi)+3*sin(pi)*i
is -3.0000 0.0000i.
But result of this code
x=3*cosd(180)+3*sind(180)*i
is -3.
Why result of second code is not in form -3.0000 0.0000i.???
How can I do this without transformation from deg to rad???
Thank you
x=3*cos(pi)+3*sin(pi)*
  1 Commento
Matt Kindig
Matt Kindig il 18 Feb 2013
Modificato: Matt Kindig il 18 Feb 2013
In short, numerical precision. In the first case, MATLAB represents sin(pi) as 3.6739e-16 (on my x64 machine), while in the second case, sind(180) is identically zero. Both are equivalent.

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Risposta accettata

Azzi Abdelmalek
Azzi Abdelmalek il 18 Feb 2013
Modificato: Azzi Abdelmalek il 18 Feb 2013
Because of precision problem with pi
sin(pi)=1.2246e-16
and
sind(180)=0

Più risposte (1)

Youssef  Khmou
Youssef Khmou il 18 Feb 2013
Modificato: Youssef Khmou il 18 Feb 2013
hi Jhon,
i can not say why using cosd and sind gives only double not complex, but you can use exponential representation which is commonly used in Elec,Eng :
R= Magnitude * exp(j* Angle ) in radian
r=3*exp(j*pi)

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