Advice on a few bottlenecks in my code

According to the profiler, I have four lines of code taking up 99% of my CPU time.
if(statment)
pCond = (bold_Phi(k,2) <= data(thisIdx : idx, 7));
else
pCond = (data(thisIdx : idx, 7) <= bold_Phi(k,2));
end
IDY = find( (data(thisIdx : idx, 1) == -1) & (pCond) & (data(thisIdx : idx, 11) == bold_Phi(k,p + 10)) );
IDZ = find( (dV(thisIdx : idx, :) <= -bold_Phi(k,3)) & (pCond) & (sCond) );
where bold_Phi and data are 2D matrices and dV is a vector.
I dont think the time penalty is coming from the indexing as the following statement is very quick
~isnan(data(thisIdx : idx, 3));
anything obvious I have missed that will help me speed up these few statements?
thank you

4 Commenti

How large are bold_Phi and dV?
dv = 1x500K. bold_Phi = 1E5 x 5E2 data = 12 x 500K.
What is statement?
Matlab2010
Matlab2010 il 22 Feb 2013
Modificato: Matlab2010 il 22 Feb 2013
statement is a bool.

Risposte (2)

If you don't need the actual indices, you can omit the find command to save time. In particular, notice that the following code blocks are equivalent but the first does not use find:
data = rand(1000,1);
isBig = data>0.5;
bigData = data(isBig);
and
data = rand(1000,1);
isBigIdx = find(data>0.5);
bigData2 = data(isBigIdx);

1 Commento

this has helped, but only a little bit. Sped up by c. 10%.
Mark Whirdy
Mark Whirdy il 22 Feb 2013
Modificato: Mark Whirdy il 22 Feb 2013

0 voti

(Almost-) Never use the find() function!
I'd need to see the contents of the variables, but at first glance you can maybe just remove it altogether with same functionality?

Questa domanda è chiusa.

Tag

Richiesto:

il 21 Feb 2013

Chiuso:

il 20 Ago 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by