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I need the Solution of this equation
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If
E=1:0.5:10;
A=2.5;
B=3.18;
C=4.25;
D=0.15;
then
S = A + B*(lnE/E)+ C*(lnE/E)^2 + D*(E/lnE)
3 Commenti
Risposte (6)
Azzi Abdelmalek
il 3 Mar 2013
syms A B C D E lnE
s=solve(A + B*(lnE/E)+ C*(lnE/E)^2 + D*(E/lnE),lnE)
E=1:0.5:10;
A=2.5;
B=3.18;
C=4.25;
D=0.15;
out=subs(s)
0 Commenti
Youssef Khmou
il 3 Mar 2013
hi,
A=2.5;
B=3.18;
C=4.25;
D=0.15;
f=@(E) A + B.*(log(E)./E)+ C.*(log(E)./E).^2 + D*(E./log(E))
E=1:0.5:10;
figure, fplot(f,E)
fsolve(f,0)
0 Commenti
Matt J
il 3 Mar 2013
Modificato: Matt J
il 3 Mar 2013
I need to fill in a few blanks for myself. If I assume that E is the unknown to solve for (your post seems to say it is a vector of data) and S is supposed to be zero (your post doesn't specify), then there are no real solutions. Your equation is quadratic in lnE/E with roots
>> r=roots([C,B-D,A])
r =
-0.3565 + 0.6791i
-0.3565 - 0.6791i
0 Commenti
dashty
il 4 Mar 2013
3 Commenti
Jan
il 4 Mar 2013
@dashty: "no answer is correctly" is not helpful. 1. It is not clear which answer are concerned by this question, because some answers could be posted afterwards. Of course I can compare the date and time of the answers manually, but this wastes the time of all who want to help you. 2. Instead of mentioning, that they are not correct, a detailed description between the results and your expectations would help to improve the answers. Currently the quality of the answers exceed the information density of the question. Please do not let us guess, what you want.
Azzi Abdelmalek
il 4 Mar 2013
This is not an equation:
A=2.5;
B=3.18;
C=4.25;
D=0.15;
E=1:10
S=A + B*(log(E)./E)+ C*(log(E)./E).^2 + D*(E./log(E))
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