Unable to filter data with a for loop and replace command

AA=Df{1,1};
AA(AA<1|AA>1.25)=0;
BB=Zf{1,1};
 for ii=1:length(AA);
      if AA(ii)==0
          BB(ii)=0;
     end
 end
AAA=replace(AA,0,[])
BBB=replace(BB,0,[])

Zf compliments Df. I am trying to filter data that is between 2 values into a new matrix and then have a matrix with the Zf component matrix that compliments the Df matrix. However, whenever I run this code it gives me the error

First argument must be a string array, character vector, or cell array of character vectors.

Error in Analyze (line 283)

AAA=replace(AA,0,[])

How can I get a filtered matrix of both?

[Image Analyst]

Well it says AA is not a "string array, character vector, or cell array of character vectors" but you didn't give us AA.

What does this say? Don't use semicolons and look in the command window for answers.

AA
whos AA

Please attach Zf and Df in a mat file so we can run your code.

save('answers.mat', 'Zf', 'Df');

Then use the paper clip icon to attach answers.mat.

Or else give us code how to create those variables.

Answer 1

[Walter Roberson]

replace() is a text processing function. You cannot use it to delete numeric values.

AAA = AA(AA ~= 0);

or in this particular case of comparing to 0

AAA = AA(logical(AA))