Output of function not variable I assign

When I run this function I want that vector to be called u so I can use it in another script file. Instead it calls it "ans" which I can't use. What is going on? Here is the function, just run it for n=4.
function [u]=finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A=zeros(n-1);
A(1,1)=1;
A(1,2)=-1;
for i=2:n-2
A(i,i-1)=-1;
A(i,i)=2;
A(i,i+1)=-1;
end
for i=n-1
A(i,i-1)=-1;
A(i,i)=2;
end
f=ones(n-1,1);
f_x=((delta_x)^2)*f;
u = (A)\(f_x);

Risposte (2)

per isakson
per isakson il 17 Mar 2013
Modificato: per isakson il 18 Mar 2013
Try the call
u = finitevolume_KG( 4 )
and make it a habit to end your functions with the keyword "end".

2 Commenti

I still omit the trailing "end" to support the small part of Matlab 6.5 users.
Yes, but "end" kind of indicates the end of the workspace of the function.

Accedi per commentare.

Jan
Jan il 18 Mar 2013
Some simplifications:
function u = finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A = zeros(n-1, n-1);
A(1,1) = 1;
A(1,2) = -1;
A(2:n-2, 1:n-3) = -1;
A(2:n-2, 2:n-2) = 2;
A(2:n-2, 3:n-1) = -1;
A(n-1, n-2) = -1;
A(n-1, n-1) = 2;
u = A \ (delta_x ^ 2 * ones(n-1, 1));

Richiesto:

il 17 Mar 2013

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