plot command is not work in Gauss Seidel Method

2 visualizzazioni (ultimi 30 giorni)
A = [
1 0 -1 0 0 0 0
-1 1 1 0 0 0 0
0 -1 2 -1 0 0 0
0 -1 0 2 0 1 0
0 -1 -1 0 2 1 1
0 0 1 -1 0 2 -1
0 0 0 -1 1 -1 2
];
b = [0 0 0 0 0 20 0]';
x=[1 1 1 1 1 1 1];
n=size(x,1);
normVal=Inf;
tol=1e-5; itr=0;
%%Gauss Seidel Method
while normVal>tol
x_old=x;
for i=1:n
sigma=0;
for j=1:i-1
sigma=sigma+A(i,j)*x(j);
end
for j=i+1:n
sigma=sigma+A(i,j)*x_old(j);
end
x(i)=(1/A(i,i))*(b(i)-sigma);
end
itr=itr+1;
normVal=norm(x_old-x);
end
%%
fprintf('system solution : \n%f\n%f\n%f\n%f in %d iterations',x,itr);
hold on
plot(itr,x, '+')
xlim([0 10])
ylim([0 2])
hold off
end

Risposta accettata

John D'Errico
John D'Errico il 4 Dic 2020
When you tell us that something does not work, you need ot explain why you THINK it does not work. In fact, plot worked perfectly well there. At least, it tiried to work as well as it could.
itr
itr =
2
x
x =
0 1 1 1 1 1 1
plot(itr,x, '+')
So itr is the number 2. x is a vector. What did you expect it to do?
  2 Commenti
suketu vaidya
suketu vaidya il 4 Dic 2020
hello ,
i is not shosws full vactor x . i means x1 = 0 x2 = 1 x3=1 and so on . i want a graph that shows x1,x2,x3 in x axist and on y axis value of x1,x2,x3 and so on
suketu vaidya
suketu vaidya il 4 Dic 2020
easy way i try to plot ans of gauss seidel method

Accedi per commentare.

Più risposte (1)

suketu vaidya
suketu vaidya il 4 Dic 2020
right ans is
hold on
plot(x,'o')

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