# Index exceeds the number of array elements: in case of for loop.

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Maria Imdad il 9 Dic 2020
Commentato: David Hill il 9 Dic 2020
I have this code where simple permutation will be performed , but i am getting an error message as "Index exceeds the number of array elements (8)."
k4='00000000000000000000000000000000';
k4=reshape(k4,8,[]);
k4=bin2dec(k4);
Perm=[0 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 ...
1 5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 ...
2 6 10 14 18 22 26 30 34 38 42 46 50 54 58 62 ...
3 7 11 15 19 23 27 31 35 39 43 47 51 55 59 63];
for i = 1:8
j4(i)=k4(Perm(i)+1);
end
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Maria Imdad il 9 Dic 2020
how should i update my loop, so that it permutes all of the 8 values in k4?
David Hill il 9 Dic 2020
k4 is all zeros. What do you mean by permuting all 8 values? Provide an example.

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### Risposte (1)

Timo Dietz il 9 Dic 2020
Modificato: Timo Dietz il 9 Dic 2020
k4 has 8 members.
But the third member of Perm is 8. So plus one leads to 9 which is more than k4 contains k4(Perm(i)+1) = k4(9);
To me it's not clear what you try to do. Could you please give an example of the expected result?
Btw., are you aware of the built-in "permute" function?
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Daniel Pollard il 9 Dic 2020
What do you mean by permute in this context?
Timo Dietz il 9 Dic 2020
Modificato: Timo Dietz il 9 Dic 2020
If you just want to rearrange k4, as I wrote, "permute" is the function you need.
But certainly you can't use a higher index in your Perm array than present in k4.

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