how can i convert an integer to an array in this function?
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function a=get_array_num(n)
end
requirments:
1.no loops,if,recurion or logical operatos
2.no num2str or str2num
3.length_of(n)=number of digits in "n" (help function)
i think maybe logspace is useful here...but how?
8 Commenti
Walter Roberson
il 31 Mar 2013
That does not define any return value "a".
The only way that you can meaningfully have length(n) be the same as the number of digits in n, is if n is a scalar value (length 1) with a single digit.
Zaza
il 31 Mar 2013
Image Analyst
il 31 Mar 2013
Modificato: Image Analyst
il 31 Mar 2013
That would mean your "a" (now called "r") is an array of 1 - not really much of an array. Besides - that code uses recursion, which is not allowed.
Zaza
il 31 Mar 2013
Walter Roberson
il 1 Apr 2013
Why is length_of(0) 1 instead of 0? Why is length_of(-23) 1 instead of 3?
Zaza
il 1 Apr 2013
Jan
il 2 Apr 2013
For length_of() the log10 function would be much smarter.
Risposte (1)
Image Analyst
il 31 Mar 2013
How about
a = zeros(n);
or
a = n * ones(1, 10);
or something similar? There is an infinite variety of arrays you could make that would full those requirements, though requirement #3 is not well explained at all (no idea what it even means).
16 Commenti
Walter Roberson
il 31 Mar 2013
I see nothing in the requirements that the output must have any relationship to the input.
Image Analyst
il 31 Mar 2013
True, so there are even more infinite ways to answer. This is so poorly described, even with additional comments, that I don't even know how to help anymore.
Walter Roberson
il 1 Apr 2013
You have not indicated what the result of the function is to be.
Zaza
il 1 Apr 2013
Image Analyst
il 1 Apr 2013
strN = num2str(n) % Convert to string.
a = strN - '0' % Convert characters to separate numbers.
Walter Roberson
il 1 Apr 2013
num2str() was prohibited in the assignment.
Image Analyst
il 1 Apr 2013
What a stupid requirement. Then use sprintf() as the "loophole":
strN = sprintf('%d',n)
a = strN - '0'
Walter Roberson
il 1 Apr 2013
Perhaps you should post the exact assignment.
Image Analyst
il 1 Apr 2013
I did it in 5 lines with a for loop, rem(), floor(), and finally fliplr() to reverse the last digits.
- for
- call rem
- reassign n
- end
- call fliplr
I'm sure you don't want me to just give you the answer outright (because you could be considered as not doing your own work) so give that a try.
Walter Roberson
il 1 Apr 2013
The requirements include 'no loops'
Image Analyst
il 1 Apr 2013
Ha! I give up. Who wants to work like that? I hate it when they say to use MATLAB but don't let you use any of the power of it. I don't see the point. I don't see any way, off the top of my head, to march along the digits of your integer if you can't use strings, loops of any type, or recursion if your integer is of unknown length. Of course if you know it's always 4 digits, then you can just write the contents of the for loop 4 times. Good luck with it though. If something strikes me, I'll post a hint.
Walter Roberson
il 1 Apr 2013
I can do it in one smallish line, once given the length_of function. Loops may have been prohibited but ":" has not been.
Zaza
il 2 Apr 2013
Jan
il 2 Apr 2013
@Zaza: It consumed some time and energy to bring you to post an explicit example. We get some parts of the problem distributed to the question and over several comments. Therefore an efficient answer is impossible.
Please edit the original question and insert all available information. Then show us, what you have tried so far, because of course we are not going to solve your homework: you couldn't submit it anymore without cheating!
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