code with out using loops

how can I write a code segment that flips an N*M array up to down *Do not use loops or flip function

[James Tursa]

What have you done so far? What specific problems are you having with your code?

[Stephen23]

Backup of original thread with question by omar khasawneh on 25th December 2020:

http://web.archive.org/web/20201227061006/https://www.mathworks.com/matlabcentral/answers/702422-code-with-out-using-loops

Answer 1

[Image Analyst]

What did your course tell you about indexing? Like

indexes = startingValue : stepValue : endingValue;

If you still need help, reply only after reading the link below:

How do I get help on homework questions on MATLAB Answers? - MATLAB Answers - MATLAB Central

[omar khasawneh]

sorry , is there any mistake with my question ? !

[Image Analyst]

Do you want us to do your homework for you so that you can turn in our code to your class while telling your professor that you wrote the code yourself? Please explain what you want us to do for you and what you will do with our answer.

[omar khasawneh]

Listen , I never allow you to accuse me of lying to my professor, if you also lie, that's your problem.

I asked because I really need help, I don't need to manipulate as you pretend, and I didn't ask you to solve the question

[Image Analyst]

Read my comment again - there is no accusation. Just a question as to explain how we can help you with this question that can be solved in one line of code. Since it's only one line of code, it's hard to help you without doing the whole thing for you. That's why I gave the hint I did. If I give any more than that, then it's completely done and there is nothing more for you to do. At least this way, I think you can change variable names and be able to say you did it yourself.

[Jan]

@omar khasawneh: There is no accusation. Image Analyst gave you a useful hint.

Answer 2

[omar khasawneh]

okay , I got it ...

I solved like this A = [1 2 3 ; 4 5 6; 7 8 9];

A = A' % transpos

A = rot180(A) %rotation

[Image Analyst]

OK, that works as long as you have written a special rot180() function. I'm not seeing it in base MATLAB. If I instead use imrotate() to do that part:

A = [1 2 3 ; 4 5 6; 7 8 9];
A = A'  % transpos
% A = rot180(A2)  %rotation
A = imrotate(A, 180)

I get

A =

1 4 7

2 5 8

3 6 9

A =

9 6 3

8 5 2

7 4 1

Which is not flipped up to down. It also flips left to right.

The solution most MATLABers would use is a single line of code using the hint I gave. So here is a little bit more:

A = A(startingValue : stepValue : endingValue, :);

That's it. One single line of code. See if you can supply the values.