Can someone solve this Error for me? Thank you

1 visualizzazione (ultimi 30 giorni)
Tianlan Yang
Tianlan Yang il 18 Mar 2021
Commentato: KSSV il 18 Mar 2021
Here is the function:
function [L,U] = eluinv(A)
[~,n]=size(A);
[L,U] = lu(A);
format compact
if closetozeroroundoff(A,7) == closetozeroroundoff(L*U,7)
disp('Yes, I have got LU factorization')
end
if closetozeroroundoff(rref(U),7) == closetozeroroundoff(rref(A),7)
disp('U is an echelon form of A')
else
disp('Something is wrong')
end
if rank(A) ~= min(size(A))
sprintf('A is not invertible')
invA=[];
return
else
leye = [L eye(n)];
ueye = [U eye(n)];
invLech = rref(leye);
invUech = rref(ueye);
invL = invLech(:,(n+1):size(invLech,2));
invU = invUech(:,(n+1):size(invUech,2));
invA = invU*invL;
if isequal(closetozeroroundoff(invA-inv(A),7),zeros(size(A)))
disp('Yes, LU factorization works for calculating the inverses')
else
disp('LU factorization does not work for me?!')
end
end

Risposte (1)

KSSV
KSSV il 18 Mar 2021
Replace lines:
leye = [L eye(n)];
ueye = [U eye(n)];
with:
leye = [L eye(size(L,1))];
ueye = [U eye(size(U,1))];
  2 Commenti
Tianlan Yang
Tianlan Yang il 18 Mar 2021
That works. However, there exist another mistake. Can you help solve this as well?
KSSV
KSSV il 18 Mar 2021
This error is clear, if you want to find the inverse of a matrix, the matrix should be a square matrix.

Accedi per commentare.

Categorie

Scopri di più su Operating on Diagonal Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by